Nitrogen and hydrogen gases are combined at high temperatures and pressures to produce ammonia, NH3. If 104.6 g of N2 are reacted with excess H2, how many moles of NH3 will be formed?
To determine the number of moles of NH3 formed, we first need to calculate the number of moles of N2 reacted.
To do this, we will use the molar mass of N2, which is 28.02 g/mol.
Number of moles of N2 = (mass of N2) / (molar mass of N2)
= 104.6 g / 28.02 g/mol
≈ 3.73 mol
According to the balanced equation, 1 mol of N2 reacts to produce 2 mol of NH3. Therefore, the number of moles of NH3 formed will be double the number of moles of N2.
Number of moles of NH3 = 2 * (number of moles of N2)
= 2 * 3.73 mol
≈ 7.46 mol
Therefore, approximately 7.46 moles of NH3 will be formed.
To find the number of moles of NH3 formed, we first need to calculate the number of moles of N2 reacted.
We can use the molar mass of N2 to convert the mass of N2 into moles. The molar mass of N2 is approximately 28.02 g/mol.
Number of moles of N2 = Mass of N2 / Molar mass of N2
Given that the mass of N2 is 104.6 g, we can calculate the moles of N2:
Number of moles of N2 = 104.6 g / 28.02 g/mol
Now, we will use the balanced chemical equation to determine the mole ratio between N2 and NH3. From the balanced equation:
N2 + 3H2 -> 2NH3
We can see that 1 mole of N2 reacts with 2 moles of NH3.
So, the number of moles of NH3 formed would be:
Number of moles of NH3 = Number of moles of N2 * (2 moles of NH3 / 1 mole of N2)
Substituting the value of the number of moles of N2 calculated earlier into the equation:
Number of moles of NH3 = (104.6 g / 28.02 g/mol) * (2 moles of NH3 / 1 mole of N2)
Now, we can calculate the number of moles of NH3.
Worked example. Follow the steps.
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