Algebra- word problem

Jordan has a photograph on his wall that is 3 in. long and 6 in. wide. He takes it to be framed which increases the length and width by 2 in. each. How does getting the picture framed change the amount of wall space needed?

My choice is B- Correct??

Choices
A. the wall needed is increased by 22in^2
B, the wall space needed is increased by 2in^2
C. the wall needed is increased by 16in^2
D. the wall space needed is increased by 4in^2

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asked by Mary
  1. original area:
    A = L*W
    A = 6*3 = 18 in^2
    new area:
    A' = L'*W'
    A' = 8*5 = 40 in^2
    the difference between these areas is the amount of wall space needed:
    40-18 = 22 in^2

    thus it's A.

    hope this helps~ :)

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    posted by Jai
  2. Thank you Jai
    could you look at my other problems?

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    posted by Mary
  3. sure~ :)

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    posted by Jai

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