Many years ago, a cruise liner sank in the middle of the Pacific Ocean. The survivors luckily landed on a remote desert island. There was enough food for the 220 people to eat once per day; this would make the food last for three weeks. Six days later a rescue ship appeared, unluckily this ship also sank, leaving another 55 people stranded on the island to now share what remained of the original food. The food obviously had to be rationed again. Everyone was now on one-half of the original ration; so how many days in total would the food last for, from the day of the original sinking?
Let r be the original ration. Write everything in terms of days, and try to come up with an equation. What do you get?
r=220x21
Can anyone help me???????
To find out how many days the food would last from the day of the original sinking, we need to calculate the total number of people who need to be fed and the amount of food available.
Let's break it down step by step:
1. Initially, there were 220 survivors with enough food to last for three weeks. Since one week is seven days, the initial food supply would last 3 weeks * 7 days = 21 days.
2. After six days, a rescue ship arrived but sank, leaving another 55 people stranded on the island. So now there are a total of 220 survivors + 55 newly stranded people = 275 people to feed.
3. Since the food supply was halved due to the increased number of people, each person would now receive one-half of the original ration. This means each person receives 1/2 * 1/1 = 1/2 of the original ration.
4. To calculate how many days the remaining food will last, we multiply the original number of days (21 days) by the ratio of the remaining food to the original ration (1/2).
21 days * (1/2) = 21/2 = 10.5 days
Therefore, the food would last a total of 10 and a half days from the day of the original sinking, considering the increased number of people and the rationing of the food supply.