a body moving along a straight line at 20 m/s undergoes an acceleration of 4 metre per second square.after two seconds what will be its speed? also, find the displacement .
1. V = Vo + at.
20 + 4*2 = 28m/s.
2. d = Vo*t + at^2.
d = 20*2 + 4*2^2 = 56m.
To find the final speed of the body after two seconds, we can use the formula:
final speed = initial speed + (acceleration × time)
Given:
Initial speed (u) = 20 m/s
Acceleration (a) = 4 m/s^2
Time (t) = 2 seconds
Plugging in the values into the formula:
final speed = 20 m/s + (4 m/s^2 × 2 s)
final speed = 20 m/s + 8 m/s
final speed = 28 m/s
Therefore, the speed of the body after two seconds will be 28 m/s.
To find the displacement after two seconds, we can use the formula:
displacement = initial velocity × time + 1/2 × acceleration × time^2
Plugging in the values:
displacement = 20 m/s × 2 s + 1/2 × 4 m/s^2 × (2 s)^2
displacement = 40 m + 1/2 × 4 m/s^2 × 4 s^2
displacement = 40 m + 1/2 × 16 m^2/s^2
displacement = 40 m + 8 m^2/s^2
displacement = 48 m
Therefore, the displacement of the body after two seconds will be 48 meters.