Write a balance ionic and net equation for the following:

KOH + HC2H3O2

I came up with the following but think this is wrong:

KOH + HC2H3O2 -> H2O (l) + KC2H3O2 (aq)

That looks good to me for the full molecular equation.

Change that to the full ionic equation, then the net ionic equation. KOH should be separated into ions as well as KC2H3O2.

To write a balanced ionic equation, you need to consider the dissociation of each compound in water.

KOH dissociates completely in water into K+ ions and OH- ions:

KOH (aq) → K+ (aq) + OH- (aq)

HC2H3O2, which is acetic acid, also dissociates partially in water into H+ ions and C2H3O2- ions:

HC2H3O2 (aq) → H+ (aq) + C2H3O2- (aq)

Now, we can combine the ions that are present on both sides of the equation to write the total ionic equation:

KOH (aq) + HC2H3O2 (aq) → K+ (aq) + OH- (aq) + H+ (aq) + C2H3O2- (aq)

Finally, to write the net ionic equation, you need to eliminate any spectator ions, which are the ions that are present on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are K+ and OH-. They appear on both sides of the equation and do not undergo any change. Therefore, they can be removed from the net ionic equation:

Net ionic equation:

H+ (aq) + C2H3O2- (aq) → H2O (l) + KC2H3O2 (aq)

So, the balanced ionic equation is:

H+ (aq) + C2H3O2- (aq) → H2O (l) + KC2H3O2 (aq)