How will changing charge change the equipotential at a distance of 2 meters?

To determine how changing the charge will affect the equipotential at a distance of 2 meters, we need to understand the relationship between charge and electric potential.

The electric potential at a point near a charged object is directly proportional to the magnitude of the charge and inversely proportional to the distance from the object. This relationship is governed by Coulomb's law, which states that the electric potential (V) is given by the equation V = k * Q / r, where k is the electrostatic constant, Q is the charge, and r is the distance.

In this case, we have a fixed distance of 2 meters. Therefore, to analyze the change in the equipotential, we need to focus on how changing the charge (Q) affects the electric potential (V).

If we increase the charge while keeping the distance constant, the electric potential at the point will also increase. This is because electric potential is directly proportional to the charge. As the charge increases, the electric potential at the given distance will increase accordingly.

Conversely, if we decrease the charge while maintaining the same distance, the electric potential will decrease. A smaller charge leads to a lower electric potential at the given distance.

In summary, changing the charge while keeping the distance constant will directly influence the electric potential and, consequently, the equipotential at that specific distance.