You are allowed to omit two out of 12 questions on a quiz. How many ways can the six students be chosen?
Huh???
Not clear how the "six students" come in.
For questions only, there are 12*11 ways to choose the questions.
To solve this problem, we can apply the concept of combinations.
The number of ways to choose two questions out of twelve can be calculated using the combination formula: C(n, r) = n! / (r!(n-r)!), where n is the total number of questions (12) and r is the number of questions to be selected (2).
Using this formula, we can find the number of ways to choose two questions out of twelve: C(12, 2) = 12! / (2!(12-2)!) = 66.
Therefore, there are 66 ways to choose two questions out of twelve.
Since each student can choose any combination of two questions, we need to multiply this number of ways by the number of students. In this case, there are six students.
Therefore, the number of ways the six students can be chosen is: 6 * 66 = 396.