Four charges are placed at the four corners of a square of side 15 cm. The charges on the upper left and right corners are +3 µC and -6 µC respectively. The charges on the lower left and right corners are -2.4 µC and -9 µC respectively. The net electric force on -6 µC charge is:

To find the net electric force on the -6 µC charge, we need to calculate the electric forces due to each of the individual charges and then add them up vectorially.

Let's label the charges as follows:
Upper left corner (+3 µC)
Upper right corner (-6 µC)
Lower left corner (-2.4 µC)
Lower right corner (-9 µC)

The formula to calculate the electric force between two charges is given by Coulomb's Law:

F = (k * |q1| * |q2|) / r^2

Where:
F is the electric force
k is the Coulomb's constant (k = 9 × 10^9 N·m^2/C^2)
|q1| and |q2| are the magnitudes of the charges
r is the distance between the charges

First, let's calculate the electric force due to the upper left charge on the -6 µC charge:
F1 = (9 × 10^9 N·m^2/C^2) * (3 µC) * (6 µC) / (15 cm)^2

Simplifying this:
F1 = (9 × 10^9 N·m^2/C^2) * (3 × 10^-6 C) * (6 × 10^-6 C) / (0.15 m)^2

F1 = (9 × 3 × 6 × 10^-6 × 10^-6 × 10^9 N·m^2/C^2) / (0.15^2 m^2)

F1 = (162 × 10^-12 N·m^2/C^2) / 0.0225 m^2

F1 ≈ 7.2 × 10^-11 N

Next, let's calculate the electric force due to the lower left charge on the -6 µC charge:
F2 = (9 × 10^9 N·m^2/C^2) * (2.4 µC) * (6 µC) / (15 cm)^2

Simplifying this:
F2 = (9 × 10^9 N·m^2/C^2) * (2.4 × 10^-6 C) * (6 × 10^-6 C) / (0.15 m)^2

F2 = (9 × 2.4 × 6 × 10^-6 × 10^-6 × 10^9 N·m^2/C^2) / (0.15^2 m^2)

F2 = (129.6 × 10^-12 N·m^2/C^2) / 0.0225 m^2

F2 ≈ 5.76 × 10^-11 N

Adding up these two forces vectorially:
Net force = F1 + F2

Net force ≈ 7.2 × 10^-11 N + 5.76 × 10^-11 N

Net force ≈ 12.96 × 10^-11 N

Therefore, the net electric force on the -6 µC charge is approximately 12.96 × 10^-11 N.

To find the net electric force on the -6 µC charge, we need to calculate the individual electric forces between this charge and the other charges in the system.

The electric force between two charges can be calculated using Coulomb's Law:

F = (k*q1*q2) / r^2

where F is the electric force, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

Let's calculate the electric forces between the -6 µC charge and each of the other charges:

1. Electric force with the +3 µC charge:
F1 = (9 x 10^9 Nm^2/C^2) * (6 x 10^-6 C) * (3 x 10^-6 C) / (15 cm)^2

Here, q1 = 6 µC (the magnitude of the -6 µC charge) and q2 = 3 µC (the magnitude of the +3 µC charge).

2. Electric force with the -2.4 µC charge:
F2 = (9 x 10^9 Nm^2/C^2) * (6 x 10^-6 C) * (2.4 x 10^-6 C) / (15 cm)^2

Here, q1 = 6 µC (the magnitude of the -6 µC charge) and q2 = 2.4 µC (the magnitude of the -2.4 µC charge).

3. Electric force with the -9 µC charge:
F3 = (9 x 10^9 Nm^2/C^2) * (6 x 10^-6 C) * (9 x 10^-6 C) / (15 cm)^2

Here, q1 = 6 µC (the magnitude of the -6 µC charge) and q2 = 9 µC (the magnitude of the -9 µC charge).

Now, to find the net electric force on the -6 µC charge, we need to add up these three forces:

Net force = F1 + F2 + F3

Please plug in the values, calculate the individual forces, and add them up to get the net electric force on the -6 µC charge.

trtytyyyvvvvvvvvv