A rectangular box of negligible mass measures 5m by 1m by .5m. How many kgs of mass can be loaded onto the box before it sinks in the water?
V=5*1*.5 = 2.5m^3
density of water =1g/cm^3 =1000 kg/m^3
I also know that when the density of the mass is greater than the density of water then the mass will sink. How would I solve this problem? Thanks in advance for your help.
To solve this problem, you need to determine the amount of mass that can be loaded onto the box before it sinks in water. Here's how you can do it:
1. Calculate the volume of the box by multiplying its length, width, and height:
V = length * width * height = 5m * 1m * 0.5m = 2.5m^3
2. Determine the density of water, which is given as 1g/cm^3 = 1000 kg/m^3.
3. Use the concept that when the density of an object is greater than the density of water, the object will sink. In this case, the box will sink when the mass loaded onto it results in a density greater than the density of water.
4. To find the mass that can be loaded without sinking, multiply the volume of the box by the density of water:
mass = volume * density of water = 2.5m^3 * 1000 kg/m^3 = 2500 kg
Therefore, you can load up to 2500 kg of mass onto the box before it sinks in water.