algebra 2

consecutive odd integer problem
find two odd integers the sum of whose squares is 130.
(sq)=squared

let x= 1st odd int
let x+2=2nd odd int

(2x+2)(2x+2)=130
4x(sq) + 4x+ 4x +4=130
4x(sq) + 8x -126= 0

2(2x(sq)+4x-63)=0
My question:
the two numbers to factor the equation.
pair of #s that multiplies to -126
and the same pair that adds to a 4.

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asked by harry
  1. found it set it up wrong was the problem :)

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    posted by harry

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