ideal gas is kept under constant pressure of 1 atm. If initial temperature is 301K and the volume increases by 10% what is the final temperature of the gas?
T2=?
V1/V2= T1/T2
V1/V2= (301K)/T2
.10/1= (301K)/T2
Is the side with volume correct? The 10% part confuses me. Thanks for your help.
To solve this problem, you can use the equation for the relationship between initial and final temperatures and volumes of an ideal gas under constant pressure. The equation is:
(V1/V2) = (T1/T2)
where V1 and V2 are the initial and final volumes respectively, and T1 and T2 are the initial and final temperatures respectively.
In this case, you are given that the initial pressure (P) is constant at 1 atm, so the equation becomes:
(1/V2) = (301K/T2)
You mentioned that the volume increases by 10%. To express this mathematically, the final volume (V2) would be equal to 110% of the initial volume (V1). Therefore, V2 = 1.1 * V1.
Substituting this value into the equation, we get:
(1 / (1.1 * V1)) = (301K / T2)
Now we can rearrange the equation to solve for the final temperature (T2):
T2 = (301K * 1.1) / V1
Plugging in the given initial temperature (T1 = 301K), we can now calculate the final temperature (T2):
T2 = (301K * 1.1) / V1
Please note that we don't have the value of the initial volume (V1) in this question. To find the final temperature accurately, you would need the initial volume as well.