SOLVE:
(3x-5)^3
that's to the third power
Solving implies that you are dealing with an equation.
You did not give an equation.
sorry ...it is cubing binomials and the avove problem
What is it equal to??
You still did not state the "equation"
It should look something like
(3x-5)^3 = ????
are you just expanding (3x+5)^3
you could do it the long way by doing
(3x+5)(3x+5)(3x+5)
or you could use Pascal's triangle whose third row has coefficients 1 3 3 1
so
(3x+5)
= 1(3x)^3 + 3(3x^2)(5) + 3(3x)(5^2) + 5^3
= 27x^3 + 135x^2 + 225x + 125
great!!! thanks so much ...... you are a life saver!!!!! =)
To solve the expression (3x-5)^3, we can follow these steps:
Step 1: Expand the expression using the binomial theorem. According to the binomial theorem, (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3, where a and b are the terms within the parentheses.
Applying this to the given expression, we have:
(3x - 5)^3 = (3x)^3 + 3(3x)^2(-5) + 3(3x)(-5)^2 + (-5)^3
Step 2: Simplify the expression by multiplying and combining like terms.
(3x)^3 simplifies to 27x^3.
3(3x)^2(-5) simplifies to -90x^2.
3(3x)(-5)^2 simplifies to -225x.
(-5)^3 simplifies to -125.
Therefore, the expanded and simplified expression is:
(3x - 5)^3 = 27x^3 - 90x^2 - 225x - 125.
So, the solution to the expression (3x - 5)^3 is 27x^3 - 90x^2 - 225x - 125.