given 14g silver oxide, how much silver can be made?
14 g Ag2O x (2*molar mass Ag/molar mass Ag2O) = ??
0.93 grams
To determine the amount of silver that can be made from 14g of silver oxide, you'll need to know the stoichiometry of the reaction between silver oxide and silver.
The balanced equation for the reaction is:
2 Ag2O → 4 Ag + O2
From this equation, we can see that 2 moles of Ag2O will produce 4 moles of Ag.
The molar mass of Ag2O is calculated as follows:
Ag: 2 x 107.87 g/mol = 215.74 g/mol
O: 16.00 g/mol
So, the molar mass of Ag2O is 215.74 + 16.00 = 231.74 g/mol.
To calculate the number of moles of Ag2O in 14g, you can use the formula:
Moles = Mass / Molar mass
Moles of Ag2O = 14g / 231.74 g/mol ≈ 0.06 mol
Since the stoichiometry of the reaction is 2:4 (Ag2O:Ag), we can multiply the moles of Ag2O by the ratio to get the number of moles of Ag produced:
Moles of Ag = Moles of Ag2O x (4 moles Ag / 2 moles Ag2O)
= 0.06 mol x (4/2)
= 0.12 mol
Finally, we can find the mass of silver using the molar mass of Ag:
Mass of Ag = Moles of Ag x Molar mass of Ag
= 0.12 mol x 107.87 g/mol
≈ 12.94 g
Therefore, approximately 12.94 grams of silver can be made from 14 grams of silver oxide.