Can you tell me if i did these right??
Lewis Dot Structure
A. BrF = 5 dots around Br-F with 5 dots around it
B. PBr3 = ? I don't know how to do because of the 3
C. NOF= 3 dots around N 2 dots around O and 5 dots around F N-O-F
D. CO = 3 dots around C double bond between O and 4 dots on oxygen
E. BrCN = 5 dots around Br double bond between C with 2 dots and -N with 3 dots Br=C-N
F. N2F2 = ?? I don't know how to do
BrF is 14 dots total. 8 around Br and 8 around F (Two dots between Br and F are counted twice to get the 8 around each).
PBr3.
 :Br:
  ..
:P:Br:
  ..
 :Br:
Add two electron to top Br, two electrons to bottom Br, and two electron to top and bottom of side Br. If I have counted right that should be 26 total.
NOF has 18 electrons so you don't have enough.
CO has 14 e. You have only 7. I can draw CO. :C:::O:
BrCN has 16 e which I think I can almost draw.
:Br:C:::N: and add 2e to top of Br and 2e to bottom of Br.
I would draw N2F2
:F:N::N:F: and add 2e to top and bottom of each F and add 2e to top or each N. Total e = 24.
YES
To determine if your Lewis dot structures are correct, we need to follow some rules. Here's a step-by-step explanation of how to draw Lewis dot structures:
A. BrF: For a Lewis dot structure, we represent the valence electrons as dots around the element symbol. Since Br (Bromine) has 7 valence electrons and F (Fluorine) has 7 valence electrons, you need to place 7 dots around each element symbol, ensuring that there is one dot on all four sides of each element.
B. PBr3: Phosphorus (P) is in group 5A, so it has 5 valence electrons. Additionally, each Bromine (Br) has 7 valence electrons. To determine how many total valence electrons are present, multiply the number of valence electrons for each element by the number of atoms of that element (in this case, P has 1 atom and Br has 3 atoms). Add these numbers together to get the total valence electrons. Using the total valence electrons, place dots around each element symbol as outlined in step A.
C. NOF: Nitrogen (N) has 5 valence electrons, Oxygen (O) has 6 valence electrons, and Fluorine (F) has 7 valence electrons. Following the same process as in step B, determine the total valence electrons and place dots accordingly.
D. CO: Carbon (C) has 4 valence electrons, while Oxygen (O) also has 6 valence electrons. Total up the valence electrons and draw the dots around each element symbol accordingly.
E. BrCN: In this molecule, Bromine (Br) has 7 valence electrons, Carbon (C) has 4 valence electrons, and Nitrogen (N) has 5 valence electrons. Once again, determine the total valence electrons and distribute the dots accordingly.
F. N2F2: In this compound, there are two Nitrogen (N) atoms, each with 5 valence electrons, and two Fluorine (F) atoms, each with 7 valence electrons. Determine the total valence electrons and place the dots around each element symbol.
Now that you have the general guidelines for drawing Lewis dot structures, you can follow the steps outlined above to check if your structures are correct.