write the balanced equation for the ionization of the weak base pyridine, C5H5N, in water
C5H5N +H2O <---> C5H6N+ + OH-
C5H5N(aq) + H2O(l) <------> C5H5NH+(aq) +
OH-(aq)
Thog
C5H5N + H2O<>C5H6N+ + OH-
To write the balanced equation for the ionization of the weak base pyridine (C5H5N) in water, you need to consider the reaction between C5H5N and water. Pyridine, being a weak base, will accept a proton (H+) from water to form its conjugate acid.
Here's the balanced equation for the ionization of pyridine in water:
C5H5N + H2O ⇌ C5H5NH+ + OH-
In this equation, pyridine (C5H5N) reacts with water (H2O) to form pyridinium ion (C5H5NH+) and hydroxide ion (OH-). The reaction is reversible, indicating that pyridinium ion can also react with hydroxide ion to regenerate pyridine and water.
Please note that this equation represents the ionization of pyridine in water, where the pyridine molecule accepts a proton from water to form a positively charged pyridinium ion and a hydroxide ion.
Pyridine is produce by synthesis reaction, A+B=C.
Therefore answer written by Alex
Nov 29, 2019 is the correct one.
thank you
THIS WAS HELPFUL
It acts just like NH3 does as a base.
NH3 + HOH ==> NH4^+ + OH^-
C6H5NH + HOH ==> C6H5NH2^+ + OH^-