college math 201

i have 50 feet of fence and the house will be the fourth side. i want a rectangular fence as big as possible. what re the dimensions?

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asked by don
  1. I assume largest area.

    P=w+2l
    area= wl
    area= (50-2l)l
    area= 50l-2l^2

    darea/dl= 0= 50-4l
    l=12.5, and w=25. In reality, one cannot adjust the size of a house to fit the area enclosed.

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