Zircon is sometimes used to make fake diamonds. What is its index of refraction if the speed of light in zircon is
1.6 x 10^8 m/s.
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Thank you.
N = c/(1.6 x 10^8 m/s.)
= 3.0/1.6
= ?
1.875
To find the index of refraction of zircon, we can use the formula:
index of refraction (n) = speed of light in vacuum (c) / speed of light in the medium (v)
Given:
Speed of light in zircon (v) = 1.6 x 10^8 m/s (given)
Speed of light in vacuum (c) = 3 x 10^8 m/s (constant)
Substitute the known values into the formula:
n = c / v
n = (3 x 10^8 m/s) / (1.6 x 10^8 m/s)
n = 1.875
Therefore, the index of refraction of zircon is approximately 1.875.