A 3.1-kilogram gun initially at rest is free to move. When a 0.015-kilogram bullet leaves the gun with a speed of 500. meters per second, what is the speed of the gun?
pbefore=pafter
m1v1+m2v2 = m1v’1+m2v’2
(3.1kg)(0m/s)+(0.015kg)(0m/s) =
(3.1kg)( v’1)+(0.015kg)(500.m/s)
0kg∙m/s=(3.1kg)( v’1)+7.5kg∙m/s
-7.5kg∙m/s=(3.1kg)( v’1)
v’1=-2.4m/s (its speed is 2.4 m/s)
u=0
0+0= 3.1 v1 + 0.015(500)m/s
-3.1v1= 7.5
v1= 7.5:(-3.1)
V1=-2.42 in absolute value then the answer will be 2.42
Stephanie is a troll
u=0
0+0=3.1V+ 0.015(500)M/S
-3.1V = 7.5
V= -2.42M/S OR 2.42m/s in absolute value
bababboey
i agree that stephanie is an absolute troll hahahah
To find the speed of the gun, we can use the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, provided no external forces act on the system.
In this case, before the bullet leaves the gun, the gun and bullet are at rest, so the total momentum is zero. After the bullet is fired, the total momentum should still be zero since no external forces act on the system. Therefore, the momentum of the gun should be equal in magnitude but opposite in direction to the momentum of the bullet.
The momentum of an object is given by the product of its mass and velocity. Let's use the following variables to solve the problem:
M1 = mass of the gun (3.1 kg)
V1 = velocity of the gun (unknown)
M2 = mass of the bullet (0.015 kg)
V2 = velocity of the bullet (500 m/s)
Using the conservation of momentum, we can write the equation:
M1 * V1 + M2 * V2 = 0
Plugging in the given values, we have:
(3.1 kg) * V1 + (0.015 kg) * (500 m/s) = 0
Solving this equation will give us the velocity (speed) of the gun:
(3.1 kg) * V1 = - (0.015 kg) * (500 m/s)
V1 = (- (0.015 kg) * (500 m/s)) / (3.1 kg)
Calculating the right side of the equation:
V1 = - 7.2581 m/s
The negative sign indicates that the gun moves in the opposite direction of the bullet. Therefore, the speed of the gun is approximately 7.26 m/s.
not the ten year old speaking haha
This a chance for you to apply the law of conservation of momentum.
That means the momentum of the gun going backward is equal and opposite to the momentum of the bullet going forward. The two momenta cancel out.
Mbullet*Vbullet = -Mgun*Vgun
Solve for Vgun