A triangle T has vertices P, Q and R. The length of the edge between P and Q is 10,
and the angles at P and Q are 60degree and 45degree respectively. What is the area of T?
(A) 50p3/(1 +p3) (B) 10p3/(1 +p3) (C) 50/(3 + 3p3) (D) 10/(3 + 3p3)(E) None of the above.
You have not defined p3. How are we supposed to choose?
Perhaops there is a figure that goes along with this question that you have neglected to provide.
Use the law of sines to compute QR or PR
With that, you can compute the triangle area exactly as (1/2)*(PQ)*(height)