The hypotenuse of a right triangle has length 8 and one of the other edges has length 3. What is the sine of the angle opposite the edge of length 3?
(A) 3/p55 (B) 3/8 (C)p55/8 (D) 55/64 (E) None of the above.
The answer is B. Reason being is that since the triangle is a right triangle that means that the angles are 45, 45, 90. Hypotenuse being 90. It tells you that one edge is 3, and in a 45, 45, 90 tringle the lengths of the sides are the same. Meaning that the other edge is also 3. Then you find the sine. The sine of anything is opposite over hypotenuse, so the answer would be 3/8.
The answer would be 3/8, but the angles are (approximately) 22,68,90
To find the sine of the angle opposite the edge of length 3, we can use the definition of sine in a right triangle. The sine of an angle in a right triangle is the length of the side opposite the angle divided by the length of the hypotenuse.
In this problem, the side opposite the angle we are interested in is the edge of length 3, and the hypotenuse has length 8. So, the sine of the angle is:
sin(angle) = (length of side opposite angle) / (length of hypotenuse)
= 3/8
Therefore, the correct answer is (B) 3/8.