Physic

If 0.045 kg of ice at 0 C is added to 0.390 kg of water at 34 C in a 0.150 kg aluminum calorimeter cup, what is the final temperature of the water?

Please help!

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  1. the sum of heats gained is zero.

    heatgainedicemelting+ heatgained by water heating+ heat gained alumin heating=0

    .045*Hfice+(.045)specheatwater*(Tf-0)+.390*specheatwater*(Tf-34)+.150specheatAl(Tf-34)=0
    solve for Tf

  2. is Hfice heat fushion of ice? or is latent heat the same as heat fushion?

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    posted by Amy
  3. so i did

    (0.45*333.55) + (0.045*4.816)(T-0) + (0.39*4.186)(T-34) + (.15*920)(T-34) = 0

    15.009 + 0.18837T + 55.51-1.63254T + 4692 - 138T = 0

    4762.519 - 139.4T = 0

    T = 34.16 C

    But I'm getting the wrong answer. Am I using the wrong number for Al? Or Hf?

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    posted by Amy

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