Calculate the amount of heat released when 100 kg of water freezes at 0 degrees celius. Delta H fusion= 6.03 kJ\mol

To calculate the amount of heat released when 100 kg of water freezes, we need to use the formula:

Q = m * ΔH

where:
- Q is the heat released (in joules),
- m is the mass of the substance (in kilograms),
- ΔH is the enthalpy change (in joules per mole).

First, we need to convert the mass of water from kilograms to grams, as the enthalpy change is given in joules per mole.

1 kg = 1000 g

Therefore, 100 kg of water is equal to 100,000 grams.

Next, we need to convert the mass of water from grams to moles. The molar mass of water (H2O) is approximately 18 g/mol.

Number of moles = Mass / Molar mass

Number of moles = 100,000 g / 18 g/mol

Number of moles ≈ 5,555.56 moles (rounded to 5 decimal places)

Now, we can calculate the heat released using the formula mentioned earlier:

Q = m * ΔH

Q = (5555.56 moles) * (6.03 kJ/mol) * (1000 J/kJ)

Q ≈ 33,500,000 Joules

Therefore, when 100 kg of water freezes at 0 degrees Celsius, approximately 33,500,000 Joules of heat are released.