find the maximum voltage that can be applied ti 8 k ohms resistor rated 50 Watt?
P = V^2/R - 50W.
V^2/8000 = 50,
V^2 = 400000,
V = 632.5 Vols,max.
To find the maximum voltage that can be applied to an 8 kΩ resistor rated for 50 Watts, we need to use Ohm's law and the power formula.
1. Start with Ohm's law, which states that V = I × R, where V is the voltage, I is the current, and R is the resistance.
2. Rearrange the formula to solve for current: I = V / R.
3. Substitute the given values: R = 8 kΩ.
4. Next, use the power formula, which states that P = V × I, where P is the power.
5. Rearrange the formula to solve for voltage: V = P / I.
6. Substitute the given power rating: P = 50 W.
Now we can solve for the maximum voltage:
1. Calculate the current using Ohm's law: I = V / R.
I = V / 8000 Ω.
2. Substitute the value of current into the power formula: V = P / I.
V = 50 W / (V / 8000 Ω).
3. Simplify the formula by multiplying both sides of the equation by V / 8000 Ω:
V = (50 W * 8000 Ω) / V.
V² = 50 W * 8000 Ω.
4. Divide both sides of the equation by 8000 Ω:
V² / 8000 Ω = 50 W.
5. Multiply both sides of the equation by 8000 Ω:
V² = 50 W * 8000 Ω.
V² = 400,000 WΩ.
6. Take the square root of both sides of the equation to find V:
V = √(400,000 WΩ).
Calculating the square root of 400,000 WΩ will give you the maximum voltage that can be applied to the 8 kΩ resistor rated for 50 Watts.