If Na has a mass of 23, and Cl a mass of 35, how many grams of NaCl are added to water to make one liter of a 3M solution?
Do you mean 3M NaCl?
molar mass NaCl = 35+23 = 58.
So you want 3 moles/L to make 3M.
Three (3) moles NaCl = 3 x 58 = ??g NaCl.
yes
To determine the mass of NaCl required to make a 3M solution in one liter of water, you first need to calculate the molar mass of NaCl.
The molar mass of NaCl (sodium chloride) is the sum of the atomic masses of sodium (Na) and chlorine (Cl).
Given that the atomic mass of Na is 23 g/mol and the atomic mass of Cl is 35 g/mol, the molar mass of NaCl is calculated as follows:
Molar mass of NaCl = atomic mass of Na + atomic mass of Cl
= 23 g/mol + 35 g/mol
= 58 g/mol
Now, let's calculate the number of moles of NaCl needed to make a 3M solution:
Molarity (M) = moles of solute / volume of solution (in liters)
Since we want a 3M solution and the volume is 1 liter, we can rearrange the equation to solve for moles of solute:
moles of solute = Molarity (M) x volume of solution (in liters)
= 3 mol/L x 1 L
= 3 mol
Finally, to find the mass of NaCl needed, we multiply the number of moles by the molar mass:
mass of NaCl = moles of NaCl x molar mass of NaCl
= 3 mol x 58 g/mol
= 174 g
Therefore, you would need to add 174 grams of NaCl to water to make one liter of a 3M NaCl solution.