A solution made from 19.0 g of NaBr and 500 mL of water has what molarity?
See above post.
How many moles of atoms are contained in 44.0g Br2
To find the molarity of a solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
To start, we need to calculate the number of moles of NaBr in the solution. To do this, we'll use the equation:
moles = mass / molar mass
The molar mass of NaBr is 102.894 g/mol. So, let's calculate the moles of NaBr:
moles = 19.0 g / 102.894 g/mol
moles ≈ 0.1849 mol
Next, we need to determine the volume of the solution in liters. The given volume is 500 mL, which is equivalent to 0.5 L.
Now, let's substitute the values into the molarity formula:
Molarity (M) = moles of solute / volume of solution in liters
M = 0.1849 mol / 0.5 L
M ≈ 0.3698 mol/L
Therefore, the molarity of the solution made from 19.0g of NaBr and 500mL of water is approximately 0.3698 M.