Write the net ionic equation for the reaction between sulfuric acid and potassium hydroxide.
I got 2H^+ + 2OH^-1 ==> 2H2O.
Is this correct??
Thanks.
Yes, it's correct. I don't know if your prof wants you to reduce it to the lowest terms. If so then you can divide all of the coefficients by 2. Follow your prof's lead.
Your net ionic equation is correct.
To explain how you arrived at this result, first, let's write the balanced chemical equation for the reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH):
H2SO4 + 2KOH → K2SO4 + 2H2O
In this reaction, sulfuric acid (H2SO4) reacts with potassium hydroxide (KOH) to form potassium sulfate (K2SO4) and water (H2O).
To write the net ionic equation, we must first determine which species are present as ions in the reaction. In this case, both sulfuric acid and potassium hydroxide are strong electrolytes, meaning they fully dissociate in solution:
H2SO4(aq) → 2H+(aq) + SO4^2-(aq)
KOH(aq) → K+(aq) + OH^-(aq)
Next, we cancel out any spectator ions that appear on both sides of the equation. In this case, potassium ions (K+) and sulfate ions (SO4^2-) are spectator ions.
Finally, we write the net ionic equation using the remaining ions:
2H+(aq) + 2OH^-(aq) → 2H2O(l)
This means that two hydrogen ions (H+) from sulfuric acid react with two hydroxide ions (OH-) from potassium hydroxide to form water (H2O).
Therefore, your net ionic equation, 2H+ + 2OH- → 2H2O, is correct.
Yes, your net ionic equation is correct. The reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) produces water (H2O) as the only product. The balanced net ionic equation for this reaction is:
2H⁺ + 2OH⁻ → 2H2O