A piece of wire when bent in the form of square encloses an area of 484cm sq.now if the same wire is bent in the form of circle area enclosed by it would be

To find the area of the circle formed by the wire, we need to determine the length of the wire first.

Let's assume the length of the wire is "L" cm. Since it is bent in the form of a square, each side of the square would be L/4 cm long. Therefore, the perimeter of the square would be 4 times the length of the side:

Perimeter of the square = 4 * (L/4) = L cm

We know that the area enclosed by the square is 484 cm^2. Since the square has four equal sides, we can find the length of each side by taking the square root of the area:

Side of the square = √484 = 22 cm

Now we can find the perimeter of the square:

L = 4 * (Side of the square) = 4 * 22 = 88 cm

To find the circumference of the circle formed by the wire, we need to set it equal to the length of the wire:

Circumference of the circle = L = 88 cm

From the formula for the circumference of a circle, we know that:

Circumference = 2 * π * r

where "r" is the radius of the circle.

By rearranging the formula, we can find the radius:

r = Circumference / (2 * π)
= 88 / (2 * 3.14159)
≈ 14 cm (approximately)

Now that we have the radius, we can find the area of the circle:

Area of the circle = π * r^2
= 3.14159 * (14)^2
= 615.752 cm^2 (approximately)

Therefore, the area enclosed by the circle formed by the wire would be approximately 615.752 cm^2.

S^2 = 484cm^2,

S = 22cm = length of each side. = dia.
of circle.

A = pi*r^2 = 3.14*(22/2)^2 = 379.9cm.