write the complete and net ionic equation for:

HCl+NaOH-->H20+NaCl

HNO3+NaOH-->H20+NaNO3

You have the complete reactions done.

net ionic:
H^+(aq) + OH^-(aq) ==> H2O(l)

To write the complete and net ionic equations for the given reactions, we need to first identify the reactants and products and then balance the equation.

1. HCl + NaOH → H2O + NaCl

Step 1: Write the balanced molecular equation.
HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)

Step 2: Break up the soluble compounds into their respective ions.
HCl(aq) → H+(aq) + Cl-(aq)
NaOH(aq) → Na+(aq) + OH-(aq)

Step 3: Identify any spectator ions. These ions do not participate in the reaction, so they can be ignored in the net ionic equation.
In this case, both Na+ and Cl- are spectator ions.

Step 4: Write the net ionic equation using only the ions involved in the reaction.
H+(aq) + OH-(aq) → H2O(l)

So, the complete ionic equation is H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) → H2O(l) + Na+(aq) + Cl-(aq)
And the net ionic equation is H+(aq) + OH-(aq) → H2O(l)

2. HNO3 + NaOH → H2O + NaNO3

Step 1: Write the balanced molecular equation.
HNO3(aq) + NaOH(aq) → H2O(l) + NaNO3(aq)

Step 2: Break up the soluble compounds into their respective ions.
HNO3(aq) → H+(aq) + NO3-(aq)
NaOH(aq) → Na+(aq) + OH-(aq)

Step 3: Identify any spectator ions. In this case, Na+ and NO3- are spectator ions.

Step 4: Write the net ionic equation using only the ions involved in the reaction.
H+(aq) + OH-(aq) → H2O(l)

So, the complete ionic equation is H+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) → H2O(l) + Na+(aq) + NO3-(aq)
And the net ionic equation is H+(aq) + OH-(aq) → H2O(l)