# Calc

Find f(x) if f(1) = −1 and the tangent line at (x, f(x)) has slope7ex + 6.
F(x)=

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1. if slope is 7ex + 6
then f(x) = (7/2)e x^2 + 6x + c
but (1,-1) lies on it
-1 = (7/2)e (1) + 6 + c
-2 = 7e + 12 + 2c
2c = -14 - 7e
c = -7 - 7e/2

f(x) = (7e/2)x^2 + 6x - 7 - 7e/2

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posted by Reiny

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