round the following number to the nearest ten: 53
to round off, first you need to know the place of the digit you want to round off,, in the problem it's "to the nearest ten". then we look at the number to the right of tens digit
if the number to the right of tens digit is:
*greater than or equal to 5, you add 1 to tens digit
*less than 5, the tens digit does not change
then the rest of the digits to the right of tens becomes zero.
for example, in 27, the ones digit is 7 and it is greater than 5. thus we add 1 to the tens digit and it becomes 30.
therefore, in 53, the ones digit is 3 and it is less than 5. thus the tens digit remains the same, and it becomes 50.
hope this helps~ :)
thank you so much..
To round the number 53 to the nearest ten, you need to consider the digit in the ones place. In this case, the digit in the ones place is 3.
When rounding to the nearest ten, you look at the digit in the ones place.
- If the digit is 0, 1, 2, 3, or 4, you round the number down to the previous ten.
- If the digit is 5, 6, 7, 8, or 9, you round the number up to the next ten.
In this case, the digit in the ones place is 3, which is less than 5. So, you round 53 down to the previous ten, which is 50.