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Law of Gravitation Find an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is neglected. The gravitational constant for g is, G = 6.67428*10^11 
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Law of Gravitationfind an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is negelcted. The gravitational constant is given as G= 6.67428*10^11 
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Law of Gravitation Find an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is neglected. The gravitational constant for g is, G = 6.67428*10^11 
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Law of Gravitation Find an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is neglected. The gravitational constant for g is, G = 6.67428*10^11 
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Law of Gravitation Find an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is neglected. The gravitational constant for g is, G = 6.67428*10^11 
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A projectile is fired with an initial velocity of v0 feet per second. The projectile can be pictured as being fired from the origin into the first quadrant, making an angle O with the positive xaxis. If there is no air 
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A projectile of mass 0.46 kg is shot from a cannon, at height 6.8 m, as shown in the ﬁgure, with an initial velocity vi having a horizontal component of 7.1m/s. The projectile rises to a maximum height of ∆y above the 
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A projectile of mass 0.46 kg is shot from a cannon, at height 6.8 m, as shown in the ﬁgure, with an initial velocity vi having a horizontal component of 7.1m/s. The projectile rises to a maximum height of ∆y above the 
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A projectile of mass 0.46 kg is shot from a cannon, at height 6.8 m, as shown in the ﬁgure, with an initial velocity vi having a horizontal component of 7.1m/s. The projectile rises to a maximum height of ∆y above the