how much heat is required to melt an ice cube that is 4.2 cm x 2.1 cm x 2.9 cm? The density of ice is 0.92 g/cm3
mass= denstiy*volume
heat= mass*Heatfusionice
To calculate how much heat is required to melt an ice cube, we need to know the mass of the ice cube, the heat required to melt one gram of ice (called the heat of fusion), and the formula:
Heat = Mass x Heat of Fusion
First, we need to calculate the mass of the ice cube using the density:
Density = Mass / Volume
Rearranging the equation, we can solve for mass:
Mass = Density x Volume
Given the dimensions of the ice cube (4.2 cm x 2.1 cm x 2.9 cm) and the density of ice (0.92 g/cm³), we can calculate the volume of the ice cube:
Volume = Length x Width x Height
Volume = 4.2 cm x 2.1 cm x 2.9 cm
Next, we convert the volume to grams of ice:
Volume = (4.2 cm x 2.1 cm x 2.9 cm) = cm³
Mass = Density x Volume (cm³)
Finally, we use the heat of fusion of ice. The heat of fusion is the amount of heat required to convert one gram of ice into water at its melting point. For ice, the heat of fusion is approximately 334 J/g.
Now we can calculate the heat required to melt the ice cube:
Heat = Mass x Heat of Fusion
Plug in the mass and the heat of fusion to get the final answer.
Note: Make sure to use consistent units (e.g., cm for length, cm³ for volume, g for mass, and J/g for heat of fusion) to get accurate results.