Two charges are separated by a distance d = 5 m. The charge q1 has a charge of q1= 7.0 µC (microcoulombs) and q2 has a charge of q2= 6.8 µC. What is the force between the charges?
Use Coulmb's Law
F = k*q1*q2/r^2
k is a constant you should know or look up.
f=9*10^9*q1q2/r^2
f=9*10^9*7*6.8/[5]^2
f=9*10^9*7*6.8/25
hence
,f=17136*10^6
To find the force between the charges, we can use Coulomb's law formula:
F = (k * q1 * q2) / (d^2)
where F is the force, k is the electrostatic constant (k = 8.99 x 10^9 N m²/C²), q1 and q2 are the charges, and d is the distance between the charges.
Let's plug in the values:
F = (8.99 x 10^9 N m²/C²) * (7.0 x 10^-6 C) * (6.8 x 10^-6 C) / (5^2 m²)
First, we need to calculate the numerator:
Numerator = (8.99 x 10^9 N m²/C²) * (7.0 x 10^-6 C) * (6.8 x 10^-6 C)
To find the force between two charges, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The formula for Coulomb's Law is:
F = (k * |q1 * q2|) / d^2
Where:
F is the force between the charges
k is Coulomb's constant, approximately equal to 9 * 10^9 Nm^2/C^2
q1 and q2 are the magnitudes of the charges (in this case, q1 = 7.0 µC and q2 = 6.8 µC)
d is the distance between the charges (in this case, d = 5 m)
Now, let's substitute the given values into the formula:
F = (9 * 10^9 Nm^2/C^2) * [(7.0 * 10^-6 C) * (6.8 * 10^-6 C)] / (5m)^2
F = (9 * 10^9 Nm^2/C^2) * [(47.6 * 10^-12 C^2)] / 25m^2
F = (9 * 10^9 Nm^2/C^2) * (1.904 * 10^-9 C^2) / (25m^2)
Now, let's calculate the force:
F = 6.8592 * 10^-1 N
Therefore, the force between the charges is approximately 0.686 N.