# Chemistry

OF2(g) + H2O(g) -> O2(g) +2HF(g) ΔH°rxn = -318 kJ

Using bond energies, calculate the bond dissociation energy of the O-F bond, in OF2.

This is the question and I got 438 as the answer, which is wrong. I don't know what I did wrong??

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1. If you will post your work I'll try to find the error. I found numbers in my book and you might check what you used. If I didn't skip a line, I read
O=O = 498
O-H = 464
HF = 569
Your numbers may differ since we aren't using the same text (I sure of that) but they should be close.

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posted by DrBob222
2. So I have
O=O = 498
O-H = 436
HF = 565

-318 = (x+436) - (498+565)

-318 = x+436 - 1063

745 = x + 436

x= 309

Isn't this what you are supposed to do? :(

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posted by Kat

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