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The formula T=2*pi*sqrt[L/32] gives the period of a pendulum of length l feet. The period P is the number of seconds it takes for the pendulum to swing back and forth once. Suppose we want a pendulum to complete three periods in 2
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What is the period, in seconds, of a simple pendulum of length 3 meters? Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places Please help! A step by step would with the answer would be helpful!
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The formula T=2*pi*sqrt[L/g] gives the period of a pendulum of length l feet. The period P is the number of seconds it takes for the pendulum to swing back and forth once. Suppose we want a pendulum to complete three periods in 2
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the length l cm of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation ),T seconds. A pendulunm with a length of 220.5cm has a period of 3s find the equation connecting l
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