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6x7=8x9-(6+7+8+9) 7x8=9x10-(7+8+9+10)

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asked by bruni
  1. Left-hand side:
    n(n+1)
    =n²+n

    Right-hand side:
    (n+2)(n+3)-(n+n+1+n+2+n+3)
    = n²+5n+6 - (4n+6)
    = n²+n

    Therefore the relation is an identity (i.e. true for all values of n)

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    posted by MathMate

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