(c) Tube (c) is again filled with water. A1 and A2 are the same as in part (b). Two pistons apply different forces to the water in the tube so that the water in the right side of the tube is a height h = 0.43m above the height of the water in the left side of the tube. If F2 = 138 N what is F1?
So first you multiply the buoyancy multiplied by gravity times the height. If we have the same problem which we do, the answer for that is 4214 Pa. Then you have to find the pressure in F2. So then do 138/.08= 1725. Then add 1725 and 4214 to get 5939. Multiply by .05.
FINAL ANSWER IS: 296.25!
Just finished it now.
916.496
To find the value of F1, we can use the principle of Pascal's law, which states that when a pressure is applied to an enclosed fluid, the pressure is transmitted equally in all directions.
In this case, we have two pistons applying forces to the water in the tube. Let's assume that A1 is the area of the piston on the left side of the tube and A2 is the area of the piston on the right side of the tube. The height difference between the right side and left side of the tube is given as h = 0.43m.
According to Pascal's law, the pressure applied by each piston can be calculated using the following formula:
P = F/A
where P is the pressure, F is the force applied, and A is the area.
Now, let's calculate the pressure on the left side of the tube, denoted as P1, and the pressure on the right side of the tube, denoted as P2.
P1 = F1/A1
P2 = F2/A2
Since the pressure is transmitted equally throughout the fluid, we have:
P1 + hρg = P2
where ρ is the density of water and g is the acceleration due to gravity.
Rearranging the equation, we get:
F1/A1 + hρg = F2/A2
Now, we can rearrange the equation to solve for F1:
F1 = (F2/A2 - hρg) * A1
Substituting the given values, we can calculate F1:
F1 = (138 N / A2 - 0.43 m * ρ * 9.8 m/s^2) * A1
Please note that to get the exact value of F1, we would need the values of A1, A2, and ρ (density of water). Without these specific values, we cannot provide a numerical answer.