How many grams of Li2SO4 are needed to prepare 250.0 mL of a 4.0% m/v Li2SO4 solution?
what is 250*.04 grams?
To find out how many grams of Li2SO4 are needed to prepare the solution, you need to use the following formula:
Mass (grams) = Volume (mL) × Concentration (g/mL)
In this case, the volume of the solution is given as 250.0 mL and the concentration is given as 4.0% m/v (mass/volume).
First, convert the concentration from a percentage to a decimal by dividing it by 100:
Concentration (decimal) = 4.0% / 100 = 0.04
Next, rearrange the formula to solve for mass:
Mass (grams) = Volume (mL) × Concentration (g/mL)
Mass (grams) = 250.0 mL × 0.04 g/mL
Now, multiply the volume by the concentration to get the mass:
Mass (grams) = 10 g
Therefore, you would need 10 grams of Li2SO4 to prepare 250.0 mL of a 4.0% m/v Li2SO4 solution.