a solution contains an unkown amount of dissolved magnesium, addition odf 0.0877 mol of Na2CO3 causes complete precipitation of all the magnesium. what is the mass of magnesium was dissovled in the solution? you must write a balanced equation for the raction in order to solve this problem.
Mg^2+ + CO3^= ==> MgCO3
0.0877 mol Mg^2+ uses that amount of CO3 and forms that amount of MgCO3.
gMgCO3 = moles MgCO3 x molar mass MgCO3.
To solve this problem, we need to write a balanced equation for the reaction between magnesium ions (Mg^2+) and carbonate ions (CO3^2-).
The balanced equation for the reaction is:
Mg^2+ + CO3^2- → MgCO3
From the equation, we can see that a 1:1 stoichiometric ratio is obtained between magnesium ions (Mg^2+) and carbonate ions (CO3^2-). This means that for every 1 mole of magnesium ions, 1 mole of magnesium carbonate (MgCO3) is formed.
In the given problem, 0.0877 moles of Na2CO3 were added, and this caused the complete precipitation of all the magnesium ions. Since Na2CO3 is a soluble compound, it will react completely with the dissolved magnesium ions, forming insoluble magnesium carbonate.
From this information, we can conclude that the number of moles of magnesium ions present in the solution is also 0.0877 moles.
To calculate the mass of magnesium dissolved in the solution, we need to know the molar mass or atomic mass of magnesium. The atomic mass of magnesium is approximately 24.31 g/mol.
Using this information, we can calculate the mass of magnesium in the solution:
Mass of magnesium = Number of moles of magnesium ions × Molar mass of magnesium
= 0.0877 moles × 24.31 g/mol
≈ 2.128 g
Therefore, the mass of magnesium that was dissolved in the solution is approximately 2.128 grams.
To solve this problem, we need to write a balanced equation for the reaction between magnesium and sodium carbonate. Let's first determine the balanced equation:
The reactants are magnesium (Mg) and sodium carbonate (Na2CO3). The products of the reaction are magnesium carbonate (MgCO3) and sodium ions (Na+).
The balanced equation for the reaction is:
Mg + Na2CO3 → MgCO3 + 2Na+
Now that we have the balanced equation, we can use stoichiometry to find the mass of magnesium dissolved in the solution.
From the balanced equation, we can see that 1 mole of magnesium reacts with 1 mole of sodium carbonate to form 1 mole of magnesium carbonate.
Given that 0.0877 moles of sodium carbonate completely precipitates all the magnesium, we can conclude that 0.0877 moles of magnesium were dissolved in the solution.
To find the mass of magnesium, we need to use its molar mass. The molar mass of magnesium is approximately 24.31 g/mol.
So, the mass of magnesium dissolved in the solution is calculated as follows:
Mass = Number of moles * Molar mass
Mass = 0.0877 mol * 24.31 g/mol
Mass ≈ 2.13 g
Therefore, approximately 2.13 grams of magnesium were dissolved in the solution.