German silver wire has a cross-sectional area of 2.047 x 10^-3 cm^2. How many meters are needed to make a resistance of 100 (omega)?
I can't find the resistivity of German silver wire. I've googled a few places, but each one gives me a different number.
Can you please tell me what the resistivity is? I need it to plug into R= resistivity (length)/area, solving for length.
You are finding different values because there is no single composition for "German silver". That is why you are finding different values for the resisitivity.
According an one online source about alloys:
<<German silver varies in composition, the percentage of the three elements ranging approximately as follows: copper, from 50% to 61.6%; zinc, from 19% to 17.2%; nickel, from 30% to 21.1%. The proportions are always specified in commercial alloys.>>
I recommend that you take an average value of the ones you have found.
According to http://www.radio-electronics.com/info/formulae/resistors/resistivity/resistivity_table.php ,
the range of resisitivity for German silver (for different alloy compositions) is
1.6 to 4.0 * 10^-6 ohm meters.
So I'd use 2.8*10^-5 ohm-m
Certainly! When it comes to finding the resistivity of German silver wire, it can indeed be challenging to find a single definitive value. The resistivity of a material can vary depending on factors such as purity, composition, temperature, and manufacturing processes. However, I can provide you with a typical range of resistivity for German silver.
The resistivity of German silver is typically around 0.000015 to 0.000020 ohm-meters (Ω·m). This value can vary slightly depending on different sources or specifications. With this range in mind, let's proceed with the calculation.
Given:
Cross-sectional area (A) = 2.047 x 10^-3 cm^2 = 2.047 x 10^-7 m^2
Resistance (R) = 100 Ω
Using the formula for resistance:
R = (resistivity x length) / A
We can rearrange the formula to solve for length (L).
L = (R x A) / resistivity
Now, plugging in the values:
L = (100 Ω x 2.047 x 10^-7 m^2) / resistivity
Since you mentioned that you haven't found a specific resistivity value, we can use the typical range I provided earlier. Let's take the average of the range by using the value 0.0000175 Ω·m.
L = (100 Ω x 2.047 x 10^-7 m^2) / 0.0000175 Ω·m
L ≈ 1.17 m
Therefore, approximately 1.17 meters of German silver wire would be needed to achieve a resistance of 100 Ω, assuming a resistivity of 0.0000175 Ω·m.
Keep in mind that this is an approximation, and the actual resistivity value of the wire might differ within the typical range provided.