A pound of body fat stores an amount of chemical energy equivalent to 3500 Cal. When sleeping, the average adult burns or expends about 0.45 Cal/h for every pound of body weight. How many Calories would a 196 lb person burn during 7 hours of sleep? (Note that 1 Cal = 1 kcal.)

Question

A pound of body fat stores an amount of chemical energy equivalent to 3500 Cal. When sleeping, the average adult burns or expends about 0.45 Cal/h for every pound of body weight. How many Calories would a 196 lb person burn during 7 hours of sleep? (Note that 1 Cal = 1 kcal.)

Answer 1

To calculate the number of calories burned during 7 hours of sleep for a 196 lb person, you will need to use the average caloric expenditure rate when sleeping.

Given that the average adult burns 0.45 Cal/h for every pound of body weight, you can multiply this rate by the person's weight (196 lb) to find the calories burned per hour:

0.45 Cal/h * 196 lb = 88.2 Cal/h

Next, multiply the calories burned per hour by the number of hours slept (7 hours) to find the total calories burned during sleep:

88.2 Cal/h * 7 hours = 617.4 Calories

Therefore, a 196 lb person would burn approximately 617.4 Calories during 7 hours of sleep.

A pound of body fat stores an amount of chemical energy equivalent to 3500 Cal. When sleeping, the average adult burns or expends about 0.45 Cal/h for every pound of body weight. How many Calories would a 196 lb person burn during 7 hours of sleep? (Note that 1 Cal = 1 kcal.)

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To calculate the number of calories burned during 7 hours of sleep for a 196 lb person, you will need to use the average caloric expenditure rate when sleeping.