Trying to figure out how to draw the structure 2-bromo-4-phenylpentane
I thought it was a five carbon strong with the ring on the second C and a Br on the 4th - but that's not correct (or not completely correct) What am I doing wrong?
2-bromo-4-phenylpentane
will have the bromine atom on the 2nd carbon (hence 2-bromo) and the ph on the 4th carbon (4-phenyl)
hence
CH3CHBrCH2CH(ph)CH3
note that this molecule has two chiral carbon atoms and so there are four possible structures.
I had the Br on the second due to the 2-bromo, and the ring on the 4th, but it was marked wrong so then I thought perhaps it should have been flipped right to left - which reading left to right would have put the Br on the 4th...I still don't understand though. Im sorry. =/
To correctly draw the structure of 2-bromo-4-phenylpentane, follow these steps:
Step 1: Determine the parent chain.
Start by identifying the longest carbon chain that contains the substituents (bromine and phenyl group). In this case, it is a 5-carbon chain (pentane).
Step 2: Identify the position of the substituents.
The name suggests that the bromine atom is attached to the second carbon, and the phenyl group is attached to the fourth carbon of the parent chain.
Step 3: Draw the carbon skeleton.
Draw a horizontal line to represent the parent chain with five carbon atoms.
- C - C - C - C - C -
Step 4: Add the substituents.
Place a bromine atom on the second carbon and a phenyl group (benzene ring) on the fourth carbon.
Br
|
- C - C - C - C - C -
|
Ph
Step 5: Complete the structure.
Fill in the remaining hydrogen atoms to satisfy the valency of each carbon atom.
Br
|
- C - C - C - C - C -
| | |
H Ph H
So, the correct structure for 2-bromo-4-phenylpentane is:
Br
|
- C - C - C - C - C -
| | |
H Ph H