A solution is prepared by adding of KOH to 1 liter of water. The resulting solution has an [OH] of 1*10 to the negative 3. What would be the pOH of this solution?
[OH-] = 1*10 to the negative 3
pOH = -log(1*10 to the negative 3)
To find the pOH of a solution, we first need to find the concentration of hydroxide ions ([OH-]) in the solution.
Given that the [OH-] is 1*10^(-3), this means that the solution is 1*10^(-3) M (moles per liter) in terms of hydroxide ions.
The pOH is calculated by taking the negative logarithm (base 10) of the hydrogen ion concentration. Since the pOH is related to the concentration of hydroxide ions, we need to take the negative logarithm of the [OH-] concentration.
pOH = -log([OH-])
pOH = -log(1*10^(-3))
Using logarithm properties, we can simplify the equation further:
pOH = -log(1) - log(10^(-3))
Recall that the logarithm of 1 is always zero, so we can simplify the equation to:
pOH = 0 - (-3)
pOH = 0 + 3
Therefore, the pOH of the solution is 3.