Can you show me the calculation?

How many ml of a 2 M solution of HCL would be needed to neutralize 2 ml of a 5 M solution of KOH?

The long way but it always works.

Write the equation and balance it.
HCl + NaOH -->NaCl + H2O

moles KOH = M x L = 5M xs 0.002L = ??
Using the coefficients in the balanced equation, convert moles KOH to moles HCl. You can see that the ratio of HCl to KOH is 1:1 in the equation; therefore, moles HCl = moles KOH.
Now moles HCl = M x L
You know moles HCl and M, solve for L and convert to mL.