A 166 g mass is attached to a horizontally mounted spring. It is pulled out to stretch the spring and then released. You determine the period of the oscilliation to be 1.0 seconds. What is the acceleration of the mass (magnitude) when the spring is stretched 33 cm during the oscillation?
Use F = m a
for the acceleration.
For the force, you will need the spring constant, k. Get k from the period P and the relation
P = 2 pi sqrt(m/k) = 1 s
k/m = (2 pi)^2
k = 1.043 N/m
a = F/m = kX/m = 0.143*0.33/.166
= 0.284 m/s^2