How many grams of bromine can be obtained by the decomposition of 92.0 of MgBr2?
Why did the scarecrow become a bromine enthusiast? Because he was always looking for "Br-ains"!
But in all seriousness, let's calculate the number of grams of bromine that can be obtained from the 92.0 grams of MgBr2.
First, we need to find the molar mass of MgBr2:
The molar mass of Mg is approximately 24.31 grams/mol.
The molar mass of Br is approximately 79.90 grams/mol.
So, the molar mass of MgBr2 would be:
(1 × 24.31) + (2 × 79.90) = 184.11 grams/mol.
Next, we'll calculate the number of moles of MgBr2 using the given mass:
92.0 grams / 184.11 grams/mol ≈ 0.500 moles of MgBr2.
Since the ratio between moles of MgBr2 and moles of bromine (Br2) is 1:2,
we can say that 0.500 moles of MgBr2 would yield 0.500 × 2 = 1.00 mole of bromine (Br2).
Finally, let's convert moles of bromine to grams:
1.00 mole × 159.80 grams/mol (molar mass of Br2) = 159.80 grams of bromine (Br2).
So, the decomposition of 92.0 grams of MgBr2 would yield approximately 159.80 grams of bromine.
To determine the number of grams of bromine that can be obtained by the decomposition of 92.0 grams of MgBr2, we need to consider the molar mass of MgBr2 and calculate the molar mass ratio between MgBr2 and bromine (Br2).
1. Determine the molar mass of MgBr2:
- The molar mass of Mg is 24.31 g/mol.
- The molar mass of Br is 79.90 g/mol.
- Since MgBr2 contains 2 bromine atoms, we need to multiply the molar mass of Br by 2.
- The molar mass of MgBr2 is then: (24.31 g/mol) + (2 x 79.90 g/mol) = 184.11 g/mol.
2. Calculate the molar mass ratio:
- The molar mass ratio between MgBr2 and bromine (Br2) is 1:2, since there are 2 bromine atoms in MgBr2.
- This means that for every 1 mole of MgBr2 decomposed, 2 moles of bromine (Br2) are obtained.
3. Calculate the moles of MgBr2:
- To find the moles of MgBr2, divide the given mass by its molar mass:
- Moles of MgBr2 = 92.0 g / 184.11 g/mol = 0.5 mol.
4. Calculate the moles of bromine (Br2):
- Since the molar ratio between MgBr2 and Br2 is 1:2, the moles of bromine produced will also be 0.5 mol x 2 = 1 mol.
5. Calculate the grams of bromine (Br2):
- Multiply the moles of bromine by its molar mass:
- Grams of bromine = 1 mol x 79.90 g/mol = 79.90 g.
Therefore, the decomposition of 92.0 grams of MgBr2 will result in 79.90 grams of bromine (Br2).
To calculate the number of grams of bromine obtained by the decomposition of 92.0g of MgBr2, we need to determine the molar mass ratio between MgBr2 and Br2.
First, let's find the molar mass of MgBr2. The molar mass of magnesium (Mg) is 24.31 g/mol, and bromine (Br) has a molar mass of 79.90 g/mol. Since there are two bromine atoms is MgBr2, we multiply the molar mass of bromine by 2.
MgBr2 molar mass = (24.31 g/mol) + (2 * 79.90 g/mol)
= 24.31 g/mol + 159.80 g/mol
= 184.11 g/mol
Next, we can calculate the moles of MgBr2 by dividing the given mass (92.0g) by the molar mass.
Moles of MgBr2 = 92.0 g / 184.11 g/mol
≈ 0.499 mol
Since the decomposition of MgBr2 yields one mole of Br2, we can say that the number of moles of bromine obtained will be equal to the number of moles of MgBr2.
Moles of Br2 = 0.499 mol
Lastly, multiply the moles of Br2 by its molar mass to find the grams of bromine obtained.
Grams of bromine = Moles of Br2 * Molar mass of Br2
≈ 0.499 mol * 159.90 g/mol
≈ 79.57 g (rounded to two decimal places)
Therefore, approximately 79.57 grams of bromine can be obtained by the decomposition of 92.0 grams of MgBr2.
Follow the steps in this example.
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