(x^2-4)^2 + (x^2-4) -6=0
Equation becoms u²+u-6=0 (u+3)(u-2)=0 so u=2=x²-4 => x²=6 => x=±√6 u=-3=x²-4 => x²=1 => x=±1 Note: A quartic equation has 4 roots.
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