Adding 1 to which digit will increase 736,419 by ten thousand?
i think is 3...
bill has four more dimes than nickels, and seven fewer nickels than pennies.he has a total of $3.35. how many of each kind of coin has he?
bill has four more dimes than nickels, and seven fewer nickels than pennies.he has a total of $3.35. how many of each kind of coin has he?
bill has four more dimes than nickels, and seven fewer nickels than pennies.he has a total of $3.35. how many of each kind of coin has he?
Say the number out loud you will know right away
To find the digit that needs to be increased by 1 to make 736,419 increase by ten thousand, we need to understand place value. The number ten thousand is represented as 10,000.
To determine which digit to increase, we start from the rightmost digit and move to the left until we reach the digit representing ten thousands (10,000). In this case, the digit in the ten thousands place is 7.
To increase 7 by 1, we add 1 to it, making it 8. Therefore, adding 1 to the digit 7 will increase 736,419 by ten thousand.
Regarding the second part of your question about Bill's coins, let's use algebra to solve it.
Let's assume the number of nickels is "n," the number of dimes is "d," and the number of pennies is "p."
According to the given information:
1) Bill has four more dimes than nickels: d = n + 4.
2) Bill has seven fewer nickels than pennies: n = p - 7.
3) The total amount of money Bill has is $3.35, which can be written as: 0.05n + 0.10d + 0.01p = 3.35.
Now, we can substitute the values from the first two equations into the third equation to solve for the values of n, d, and p.
By solving the system of equations, we can find the values for n, d, and p, representing the number of nickels, dimes, and pennies that Bill has.