a body is dropped from the roof of a builindgs 10 m high .calculate the time of fall and the speed with which it hits the ground .take g=10m/second sqare
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To calculate the time of fall and the speed at which the body hits the ground, you can use the equations of motion for free fall.
First, let's find the time of fall using the equation:
h = (1/2) * g * t^2
where:
h = height of the building = 10 m
g = acceleration due to gravity = 10 m/s^2 (downwards)
t = time of fall (unknown)
Rearranging the equation to solve for t, we get:
t^2 = (2 * h) / g
t^2 = (2 * 10) / 10
t^2 = 2
t = √2 ≈ 1.414 seconds
The time of fall is approximately 1.414 seconds.
Next, let's calculate the speed at which the body hits the ground using the equation:
v = g * t
where:
v = final velocity = speed at which the body hits the ground (unknown)
g = acceleration due to gravity = 10 m/s^2 (downwards)
t = time of fall = 1.414 seconds
Substituting the given values into the equation:
v = 10 * 1.414
v ≈ 14.14 m/s
The speed at which the body hits the ground is approximately 14.14 m/s.