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solve the equations algebraically

x^2 + y^2 = 25
3y - 4x = 0

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Camile

  1. I would use substitution, from the 2nd ....
    y = 4x/3
    sub into the first ....
    x^2 + (4x/3)^2 = 25
    x^2 + 16x^2/9 = 25
    9x^2 + 16x^2 = 225
    25x^2 = 225
    x^2 = 9
    x = ± 3

    if x=3, y = 4
    if x = -3 , y = -4

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    Reiny

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